given the points M (-3,-4) and T (5,0), find the coordinates of the point Q on direct line segment MT that partitions MT in the ratio 2:3. Write the coordinates of the point Q in decimal form.
Accepted Solution
A:
vector MT, or the change from x1 to x2 and y1 to y2 is expressed as [tex](5 - ( - 3))i + (0 - ( - 4))j \\ = 8i + 4j[/tex] no worries if you are unfamiliar with vector notation which is the the I and j there. it just shows that from point m to point t, x increases by 8 and y increases by 4. now find [tex] \frac{2}{3} 8 \: \: \: \: and \: \: \: \: \frac{2}{3} 4[/tex] that is [tex] \frac{16}{3} and \frac{8}{3} [/tex] add the 16/3 to the original value of x and 8/3 to the original value of y. the original value is point m.
now your point q should equal [tex]( \frac{16}{3} + ( - 3))x \: \: and \: \: ( \frac{8}{3} + ( - 4))y[/tex]